2cos^2(x)+sin(x)=1

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Solution for 2cos^2(x)+sin(x)=1 equation: 


Simplifying
2cos2(x) + sin(x) = 1

Multiply cos2 * x
2cos2x + sin(x) = 1

Multiply ins * x
2cos2x + insx = 1

Solving
2cos2x + insx = 1

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1insx' to each side of the equation.
2cos2x + insx + -1insx = 1 + -1insx

Combine like terms: insx + -1insx = 0
2cos2x + 0 = 1 + -1insx
2cos2x = 1 + -1insx

Divide each side by '2os2x'.
c = 0.5o-1s-2x-1 + -0.5ino-1s-1

Simplifying
c = 0.5o-1s-2x-1 + -0.5ino-1s-1

Reorder the terms:
c = -0.5ino-1s-1 + 0.5o-1s-2x-1

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